Respuesta :
Answer:
The correct option is (b) 0.333.
Step-by-step explanation:
The data provided is as follows:
Hepatitis C No hepatitis C Total
No Tattoos 5 50 55
1 Tattoo 10 210 220
> 1 Tattoo 15 150 165
Total 30 410 440
The probability of an event E is the ratio of the favorable number of outcomes to the total number of outcomes.
[tex]P(E)=\frac{n(E)}{N}[/tex]
The condition probability of an event A provided that another event X has already occurred is:
[tex]P(A|X)=\frac{P(A\cap X)}{P(X)}[/tex]
The number of people who has hepatitis C is:
n (Hepatitis C) = 30
The number of people who has hepatitis C and one tattoo is:
n (Hepatitis C and 1 Tattoo) = 10
Compute the probability that he or she has hepatitis C, given that he or she has one tattoo as follows:
[tex]P(\text{Hepatitis C} |\text{1 Tattoo})=\frac{n(\text{Hepatitis C and 1 Tattoo})}{n(\text{1 Tattoo})}[/tex]
[tex]=\frac{10}{30}\\\\=\frac{1}{3}\\\\=0.333[/tex]
Thus, the correct option is (b).
Answer:
0.045
Step-by-step explanation:
I actually took a quiz with this question, and this was the correct answer. The dude before me has the right process, but bungled it a little.
