Respuesta :
Answer:
The stationary matrix is:
S = [0.2791, 0.7209]
Step-by-step explanation:
The transition matrix, P is:
[tex]P=\left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right][/tex]
The stationary matrix S for the transition matrix P would be obtained by computing k powers of P until all the two rows of P are identical.
Compute P² as follows:
[tex]P^{2}=\left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right]\times \left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right][/tex]
[tex]=\left[\begin{array}{cc}0.2932&0.7068\\0.2736&0.7264\end{array}\right][/tex]
Compute P³ as follows:
[tex]P^{3}=P^{2}\times P[/tex]
[tex]=\left[\begin{array}{cc}0.2932&0.7068\\0.2736&0.7264\end{array}\right]\times \left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right]\\\\=\left[\begin{array}{cc}0.2810&0.7190\\0.2783&0.7217\end{array}\right][/tex]
Compute P⁴ as follows:
[tex]P^{4}=P^{3}\times P[/tex]
[tex]=\left[\begin{array}{cc}0.2810&0.7190\\0.2783&0.7217\end{array}\right]\times \left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right]\\\\=\left[\begin{array}{cc}0.2793&0.7207\\0.2790&0.7210\end{array}\right][/tex]
Compute P⁵ as follows:
[tex]P^{5}=P^{4}\times P[/tex]
[tex]=\left[\begin{array}{cc}0.2793&0.7207\\0.2790&0.7210\end{array}\right]\times \left[\begin{array}{cc}0.38&0.62\\0.24&0.76\end{array}\right]\\\\=\left[\begin{array}{cc}0.2791&0.7209\\0.2791&0.7209\end{array}\right][/tex]
For k = 5, we get both the rows identical.
The stationary matrix is:
S = [0.2791, 0.7209]
