Respuesta :

Stephen46

Answer:

a = √157

b = √85

First Question

To find a we Pythagoras theorem

That's

[tex] {a}^{2} = {6}^{2} + {11}^{2} \\ {a}^{2} = 36 + 121 \\ \\ {a}^{2} = 157 \\ \\ a = \sqrt{157} \\ [/tex]

Second question

[tex] {11}^{2} = {b}^{2} + {6}^{2} \\ \\ {b}^{2} = 121 - 36 \\ \\ {b}^{2} = 85 \\ \\ \\ b = \sqrt{85} [/tex]

Hope this helps you

Answer:

Below in bold.

Step-by-step explanation:

The first one  a^2 = 6^2 + 11^2    ( By the Pythagoras Theorem)

a^2 =  157

a = √157.

The second triangle:

b^2 = 11^2 - 6^2

b^2 = 85

b = √85.