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A fish population grew according to the following quadratic model, the number of fish a day is given by

P(t)=800t-t^2

What is the growth rate at t=600​

Respuesta :

sqdancefan

Answer:

  -400

Step-by-step explanation:

We can find the rate of change by differentiating the population function:

  P'(t) = 800 -2t

Then at t = 600, the growth rate is ...

  P'(600) = 800 -2(600) = -400

The growth rate is -400 fish per day on day 600.

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