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simplify, and write using only positive exponents. variables are non-zero (x^-4)^2(x^-2y^3)^2/(x^-2y^-3)^2

Respuesta :

Alfpfeu

Hello,

[tex]\dfrac{(x^{-4})^2(x^{-2}y^3)^2}{(x^{-2}y^{-3})^2}=\dfrac{x^{-8}x^{-4}y^6}{x^{-4}y^{-6}}\\\\=x^{-8-4+4}y^{6-(-6)}=x^{-8}y^{12}=\dfrac{y^{12}}{x^{8}}[/tex]

do not hesitate if you have any question

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