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A fish population grew according to the following quadratic model, the number of fish a day is given by

P(t)=800t-t^2

What is the average growth rate between t=400 and t=600​

Respuesta :

tramserran

Answer: -200

Step-by-step explanation:

P(t) = 800t - t²

P(600) = 800(600) - (600)²

           = 480,000 - 360,000

           = 120,000

P(400) = 800(400) - (400)²

           = 320,000 - 160,000

           = 160,000

[tex]\text{rate of change}=\dfrac{P(600)-P(400)}{600-400}=\dfrac{120,000-160,000}{200}=\dfrac{-40,000}{200}=-200[/tex]

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