Answer:
[tex]\displaystyle AB \approx 8.39 \text{ inches} \text{ and } AC \approx 13.05 \text{ inches}[/tex]
Step-by-step explanation:
Note that we are given the measure of ∠C and the length of side BC.
To find AB, we can use the tangent ratio. Recall that:
[tex]\displaystyle \tan\theta = \frac{\text{opposite}}{\text{adjacent}}[/tex]
Substitute in appropriate values:
[tex]\displaystyle \tan 40^\circ = \frac{AB}{BC} = \frac{AB}{10}[/tex]
Solve for AB:
[tex]\displaystyle AB = 10\tan 40^\circ \approx 8.39\text{ inches}[/tex]
For AC, we can use cosine ratio since we have an adjacent and need to find the hypotenuse. Recall that:
[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]
Substitute in appropriate values:
[tex]\displaystyle \cos 40^\circ = \frac{BC}{AC} = \frac{10}{AC}[/tex]
Solve for AC:
[tex]\displaystyle \begin{aligned} \frac{1}{\cos 40^\circ} & = \frac{AC}{10} \\ \\ AC & = 10\cos 40^\circ \approx 13.05\text{ inches} \end{aligned}[/tex]
In conclusion, AB is about 8.39 inches and AC is about 13.03 inches.
