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A ladder is 8m long. It leans against a wall with one end on the ground 6m from the wall. How far up the wall does the ladder reach?

Respuesta :

Step-by-step explanation:

Use pythagoras theorem

a^2=b^2+c^2

a^2=64+36

a=10m

The length up to the wall of the ladder will be around 5.2915.

What is Pythagoras theorem?

The Pythagoras theorem is a theorem used to find out any length of a right-angle triangle.

Pythogoroous theorem is

Hypotenuse² = base² + perpendicular²

Given that a ladder leans against a wall so the ladder will act like a hypotenuse.

Let 6m be the base then we have to find the perpendicular.

Hypotenuse² = base² + perpendicular²

perpendicular² = Hypotaneous² -  base²

perpendicular =  [tex]\sqrt{ (Hypotenuse)^2 - (base)^2}[/tex]

Given hypotenuse is 8m and the base is 6m.

perpendicular² = 8² - 6²

perpendicular² = 28

perpendicular = √(28) = 5.2915 hence this much be far up the wall does the ladder reach.

For more information about Pythagoras theorem.

https://brainly.com/question/343682

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