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Which equation has a graph that is a parabola with a vertex at (5, 3)?
O y = (x - 5)2 + 3
O y = (x + 5)2 + 3
O y = (x-3)2 + 5
y= (x+3)² + 5
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Respuesta :

Smile0

Answer: The equation that has a graph which is a parabola with a vertex at (5, 3) would be y = (x – 5)^2 + 3. The general form of a parabola which the vertex is not in the origin is expressed as y = a(x - h)^2 + k where (h,k) represents the vertex.

MrRoyal

The vertices of a parabola is the maximum or the minimum point on the parabola.

The equation (a) [tex]\mathbf{y = (x - 5)^2 + 3}[/tex] has a vertex at (5,3)

The equation of a parabola is represented as:

[tex]\mathbf{y = a(x - h)^2 + k}[/tex]

Where:

[tex]\mathbf{Vertex = (h,k)}[/tex]

The vertex is given as:

[tex]\mathbf{Vertex = (5,3)}[/tex]

This means that:

[tex]\mathbf{(h,k) = (5,3)}[/tex]

Substitute these values in [tex]\mathbf{y = a(x - h)^2 + k}[/tex]

[tex]\mathbf{y = a(x - 5)^2 + 3}[/tex]

By comparing the options,

[tex]\mathbf{y = (x - 5)^2 + 3}[/tex] has the same vertex as [tex]\mathbf{y = a(x - 5)^2 + 3}[/tex]

Hence, [tex]\mathbf{y = (x - 5)^2 + 3}[/tex] has a vertex at (5,3)

Read more about vertex of parabola at:

https://brainly.com/question/20333425

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