Find the distance between a point (–7, –19) and a horizontal line at y = 3. Choices are in the attachment...

Explanation:
The distance we're after is the vertical distance from the point to the line. So we only care about the difference in y values from y = -19 to y = 3
You can count out the spaces or use subtraction along with absolute value
distance from P to Q = |P-Q|
distance from -19 to 3 = |-19-3|
distance from -19 to 3 = |-22|
distance from -19 to 3 = 22
The absolute value is to ensure the result is never negative.