Answer and Explanation
Since (x + 3)^2 => 0 for all x, the smallest value of the function P(x) would be 2
When (x + 3)^2 = 0
x = -3 and y value of P(x) would be 2 (because there’s a plus 2)
So the vertex of the minimum point is (-3,2).
A) Q(x) = (x + 3)^2 + 5
Vertex is (-3,5)
B) R(x) = (x + 3 - 6)^2 + 2
As the opposite happens when you’re transforming x value.
= (x - 3)^2 + 2
Vertex is (3,2)
C) S(x) = (x + 3 - 4) ^2 + 2 - 7
= (x - 1)^2 - 5
Vertex is (1,-5)
<~>\_/<~> Ho_odini <~>\_/<~>
