21laila21
contestada

If In(y - 40) = 5x, then y =

(a)
[tex] {e}^{5x} + 40[/tex]

(b)
[tex] {e}^{5x} - 40[/tex]

(c)
[tex]5 ({e}^{x} + 40)[/tex]

(d)
[tex]5 {e}^{x} - 40[/tex]

(e)none​

Respuesta :

r3t40

If [tex]\ln(y-40)=5x[/tex] then [tex]y=e^{5x}+40[/tex].

Hope this helps.

wegnerkolmp2741o

Answer:

a  e^(5x)  +40

Step-by-step explanation:

In(y - 40) = 5x

Raise each side to base e

e^In(y - 40) = e^5x

y - 40 = e^5x

Add 40 to each side

y - 40 +40 = e^5x+40

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