aylock
contestada

the cube of the difference of 4 times x and 6 divided by 2 times the sum of x and 1
4(1 - 6)2
25 + 1
(41 – 6)
2(1 + 1)
413 - 6
2(1 + 1)
(41 - 6)
21 + 1


Respuesta :

Answer:

  [tex]\dfrac{(4x-6)^3}{2}(x+1)[/tex]

Step-by-step explanation:

Maybe you want your verbiage written as a mathematical expression.

"the difference of 4 times x and 6" is (4x -6). "the sum of x and 1" is (x+1).

No other grouping is indicated, so we have ...

  [tex]\boxed{\dfrac{(4x-6)^3}{2}(x+1)}[/tex]