Respuesta :

Explanation:

  • We need to find the amount of carbon dioxide gas in [tex]1.505\times 10^{23}[/tex] molecules of the gas.
  • We know that, 1 mole weighs 44 gram of carbon dioxide which contains [tex]6.022\times 10^{23}[/tex] number of molecules. It means that, [tex]6.022\times 10^{23}[/tex] number of molecules present in 44 grams of carbon dioxide molecule. So,[tex]1.505\times 10^{23}[/tex]  number of molecules present in :

[tex]=\dfrac{1.0505\times 10^{23}}{6.022\times 10^{23}}\times 44\\\\=7.675\ \text{grams}[/tex]

  • Hence, 7.675 grams of carbon dioxide is present in [tex]1.505\times 10^{23}[/tex] molecules of the gas.

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