For a certain health insurance policy, losses are uniformly distributed on the interval [0, b). The policy has a deductible of $180 and the expected value of the unreimbursed portion of a loss is $144. Calculate b.

Respuesta :

Answer:

b = 450

Step-by-step explanation:

Given that:

for a certain health insurance policy; Losses are uniformly distributed on the interval (0, b)

If the policy has a deductible value of $180      &

the expected value of the unreimbursed portion of a loss E(x)= $144

Then; b whican be calculated as:

[tex]f = \dfrac{1}{b}...... since \ \ \ 0 \leq x \leq b[/tex]

[tex]E(x) = P[X<180] \ E|X|X<180]+P[X \geq 180] \ E{|X| X \geq 180][/tex]

[tex]E(x) = \dfrac{180}{b}(90) + [1-\dfrac{180}{b}](180)[/tex]

we know that E(x) = 144

thus;

[tex]144= \dfrac{180}{b}(90) + [1-\dfrac{180}{b}](180)[/tex]

[tex]144= \dfrac{16200}{b} + 180 -\dfrac{32400}{b}[/tex]

[tex]144- 180= \dfrac{16200}{b} -\dfrac{32400}{b}[/tex]

[tex]-36= \dfrac{16200}{b} -\dfrac{32400}{b}[/tex]

[tex]-36= \dfrac{16200-32400}{b}[/tex]

[tex]-36= \dfrac{-16200}{b}[/tex]

-36 b = -16200

b = -16200/-36

b = 450