Answer:
[tex]P(E \cup F)=P(E)+P(F)[/tex].
Step-by-step explanation:
Given the statement
If [tex]P(E)+P(F)=P(E \cup F)+P(E \cap F)[/tex], then E and F are mutually exclusive events.
If two events are mutually exclusive, they have no elements in common. Thus, P(E∩F)=0.
Therefore, the statement is always true as P(E∩F)=0
For mutually exclusive events:
[tex]P(E \cup F)=P(E)+P(F)[/tex].