Answer:
Explanation:
Force on charge particles
F = q ( v x B )
= 1.6 x 10⁻¹⁹ x [ ( 2i+3j+4k) x .5k ] x 10⁵
= 1.6 x 10⁻¹⁴ x ( 1.5 i - j )
= (2.4 i - 1.6 j ) x 10⁻¹⁴ N
magnitude of this vector
= 2.88 x 10⁻¹⁴ N
Angle between B and v
cosθ = [tex]\frac{(2i+3j+4k).(.5k)}{\sqrt{2^2+3^2+4^2}\times .5 }[/tex]
= [tex]\frac{2}{2.69}[/tex]
cosθ = .74
θ = 42° .
