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A marble is thrown off of a balcony, towards the ground, from a height
of 18 feet above ground level, with a velocity of 4.5 feet per second.
Which function could be used to model the height of the marble, after
t seconds?

please hurry Ill make brainiest A marble is thrown off of a balcony towards the ground from a height of 18 feet above ground level with a velocity of 45 feet pe class=

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Answer:

Option (3)

Step-by-step explanation:

A stone has been thrown off towards the ground from a height [tex]h_{0}[/tex] = 18 feet

Initial speed of the stone 'u' = 4.5 feet per second

Since height 'h' of a projectile at any moment 't' will be represented by the function,

h(t) = ut - [tex]\frac{1}{2}(g)(t)^2[/tex] + [tex]h_{0}[/tex]

h(t) = 4.5t - [tex]\frac{1}{2}(32)t^2[/tex]+ 18 [ g = 32 feet per second square]

h(t) = 4.5t - 16t² + 18

h(t) =-16t² + 4.5t + 18

Therefore, Option (3) will be the answer.

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