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A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?

Respuesta :

MathPhys

Answer:

7.61 m/s

Explanation:

Given:

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

WInansj

71.6

Δx = 87.4 m

v = 21.0 m/s

t = 6.11 s

Find: v₀

Δx = ½ (v + v₀) t

87.4 m = ½ (21.0 m/s + v₀) (6.11 s)

v₀ = 7.61 m/s

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