Answer:
460V
Explanation:
The following data were obtained from the question:
Energy (E) = 11500J
Charge (Q) = 50C
Potential difference (V) =.?
The energy, E stored in a capacitor is related to the charge, Q and potential difference, V by the following equation
E = ½QV
With the above equation, we can easily calculate the potential difference as follow:
E = ½QV
11500 = ½ × 50 × V
11500 = 25 × V
Divide both side by 25
V = 11500/25
V = 460V.
Therefore, the potential difference is
460V.
