Answer:
1/20 or 0.05
Step-by-step explanation:
Assuming that all five posters are different, the number of ways to randomly place those posters is given by:
[tex]N=5*4*3*2*1 = 120\ ways[/tex]
If we want the largest to be in the center and the next largest to be on its left, two poster will have a set position and only three could be randomized:
[tex]n=3*2*1*1*1=6\ ways[/tex]
Therefore, the probability is:
[tex]P=\frac{n}{N}=\frac{6}{120} =\frac{1}{20} =0.05[/tex]
The probability is 1/20 or 0.05.
