Micaiah places coins in the order of penny, nickel, dime, penny, nickel, dime, and so on, as shown, so that each row contains one more coin than the previous row. What is the total value in cents of all coins in the 12th row?
There is 64 total cents in the 12th row. We can figure this out by adding a nickel, a dime, and a penny. So, this gives us 1 + 5 + 10, which equals 16. The 12th row consists of 4 sets of 3 consecutive coins, so we take 16 and multiply it by four. So the final answer is 64.
