Can somebody please help with these two questions?

Answer:
#3: x is approximately 0.37, -5.37, #4: x is approximately 4.19, -1.19
Step-by-step explanation:
You can solve using the quadratic equation or by solving with the perfect square
[tex]\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}[/tex] = [tex]x^{2}+5x-2=0\\ \frac{-5+/-\sqrt{5^{2}-4(1)(-2) }}{2(1)}[/tex]
x is approximately 0.37, -5.37