Answer:
[tex]P_2=50kPa[/tex]
Explanation:
Hello,
In this case, we can apply the Boyle's law in order to understand the pressure-volume relationship as an inversely proportional relationship relating the initial and the final volume:
[tex]P_1V_1=P_2V_2[/tex]
Next, we compute the final pressure P2:
[tex]P_2=\frac{P_1V_1}{V_2}=\frac{100.00kPa*500.0mL}{1000.0mL} \\\\P_2=50kPa[/tex]
Thus we validate, the higher the volume the lower the pressure.
Best regards.
