kristerChapp
contestada

find the perimeter of rectangle qrst whose vertices are q(–2, 2), r(1, 0), s(0, –1), and t(–3, 1). a. 5.02 units b. 5.09 units c. 7.29 units d. 10.04 units

Respuesta :

nobillionaireNobley
Perimeter of a rectangle = 2(l + w)
Length = [tex] \sqrt{(1+2)^2+(0-2)^2} = \sqrt{3^2+(-2)^2} = \sqrt{9+4} = \sqrt{13}=3.61 [/tex]
Width = [tex] \sqrt{(0-1)^2+(-1-0)^2} = \sqrt{(-1)^2+(-1)^2} = \sqrt{1+1} = \sqrt{2}=1.41 [/tex]

Perimeter = 2(3.61 + 1.41) = 2 x 5.02 = 10.04 units
xleepy

Answer:

D: 10.04 units

Step-by-step explanation:

Short to what is written above