1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
-2x+y=-11
y = 2x-11
3x-4y=11
3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
x =33/5
y = 11/5
2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
(-2x+6y=-12)5
-10x + 30y = -60
(5x-5y=10)2
10x - 10y = 20
Adding the two equations,
-10x + 30y = -60
10x - 10y = 20
20y = -40
y = -2
x = 0
3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
-3x-2y=-12
y = -3/2 x + 6
9x+6y=-9
y = -3/2 x - 3/2
Since the slopes are equal then they are parallel lines so they never meet at one point.