Answer: [tex]160 \Omega[/tex]
Explanation:
According to Ohm's law:
[tex]V=R.I[/tex]
Where:
[tex]V=120 V[/tex] is the voltage difference across the light bulb
[tex]R[/tex] is the resistance of the light bulb (the value we want to find)
[tex]I=0.75 A[/tex] is the electric current
Isolating [tex]R[/tex]:
[tex]R=\frac{V}{I}[/tex]
[tex]R=\frac{120 V}{0.75 A}[/tex]
Finally:
[tex]R=160 \Omega[/tex] This is the resistance of the light bulb
