106.78 J of heat is required by the iron sample.
Explanation:
We have to find the amount of heat required using the formula,
q = m × c × ΔT
where q is the heat absorbed
m is mass of the metal in grams = 4.33 g
c = specific heat of iron = 0.450 J/g °C
ΔT = change in temperature = 79.8° C - 25°C = 54.8° C
Plugin the values in the above formula, we will get,
q = 4.33 g × 0.450 J/g° C × 54.8° C
= 106.78 J
So 106.78 J of heat is required by the sample of iron.
