Respuesta :

konrad509
[tex]y=\sqrt{13x}\\ y'=\frac{1}{2\sqrt{13x}}\cdot13\\ y'=\frac{13}{2\sqrt{13x}}[/tex]
DavidOrrell
f(x) = √13x = √13 * √x = √13 * x^0.5
f'(x) = (√13 * 0.5) * x^-0.5 = ((√13)x^-0.5)/2 = √13 / 2x^0.5 = √13 / 2√x

Hence, the derivative of y is √13 / 2√x