Respuesta :
base pay + (rate * sales) = total pay
b + r(400) = 388
b + r(700) = 454
b = 388 - 400r
now sub into 2nd equation
388 - 400r + 700r = 454
-400r + 700r = 454 - 388
300r = 66
r = 66/300
r = 0.22...22% is the rate
substitute for r
b + 400r = 388
b + 400(0.22) = 388
b + 88 = 388
b = 388 - 88
b = 300
so ur equation is : y = 0.22x + 300
y = 0.22(2600) + 300
y = 572 + 300
y = 872......so her salary when selling $2600 worth of stuff is $872
b + r(400) = 388
b + r(700) = 454
b = 388 - 400r
now sub into 2nd equation
388 - 400r + 700r = 454
-400r + 700r = 454 - 388
300r = 66
r = 66/300
r = 0.22...22% is the rate
substitute for r
b + 400r = 388
b + 400(0.22) = 388
b + 88 = 388
b = 388 - 88
b = 300
so ur equation is : y = 0.22x + 300
y = 0.22(2600) + 300
y = 572 + 300
y = 872......so her salary when selling $2600 worth of stuff is $872
On solving the linear equations with two variables, Carissa's salary when she sells $2,600 worth of merchandise is $872.
What are linear equations in two variables ?
The linear equations in two variables are of the highest exponent order of 1 and have one, none, or infinitely many solutions. The standard form of a two-variable linear equation is ax+ by+ c= 0 where x and y are the two variables. The solutions can also be written in ordered pairs.
Let Carissa's fixed salary be $x.
Let Carissa's varying salary based on the merchandise sold be $y.
x + 400y = 388
x + 700y = 454
Subtracting the two equations-
300y = 66
y = 0.22
Putting the value of y in equation 1 -
x = 388 - 400 * 0.22 = 300
Carissa's salary when she sells $2,600 worth of merchandise = 300 + 2600 * 0.22 = $872
Learn more about linear equations in two variables here
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