Respuesta :

dalendrk
[tex]The\ equation\ of\ the\ circle:\\\\(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)-center;\ r-radius.\\-------------------\\\\(-5;-5)\to a=-5;\ b=-5\\2r=13\to r=6.5\\\\\boxed{(x+5)^2+(y+5)^2=6.5^2}[/tex]
FirstSineOfMadness
The equation for a circle with center at coordinates (h,k) with radius r is:
(x-h)^2+(y-k)^2=r^2
Substituting in your values we get
(x+5)^2+(y+5)^2=6.5^2
Using foil you can expand it to:
x^2+10x+y^2+10y+50=42.25
Subtract 50 from both side to get:
x^2+10x+y^2+10y=-7.75

Final Answer:
(x+5)^2+(y+5)^2=6.5^2
Or
x^2+10x+y^2+10y=-7.75
Hope I helped :)