Which expression gives the solutions of –5 + 2x² = –6x?

We are given with the expression –5 + 2x² = –6x in which the standard form is 2x² + 6x - 5 = 0 . There are two roots to be identified as expected. Through the quadratic equation, we can identify the a, b and c. Using the equation, the roots are 0.679 and -3.679. The expression is {0.679, -3.679}

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calculista calculista · Answer 2 · 2019-02-01T04:29:28+01:00

Answer:

[tex]x=\frac{-3(+/-)\sqrt{19}} {2}[/tex]

Step-by-step explanation:

we have

[tex]-5+2x^{2} =-6x[/tex]

Rewrite

[tex]2x^{2}+6x-5=0[/tex]

we know that

The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]2x^{2}+6x-5=0[/tex]

so

[tex]a=2\\b=6\\c=-5[/tex]

substitute

[tex]x=\frac{-6(+/-)\sqrt{6^{2}-4(2)(-5)}} {2(2)}[/tex]

[tex]x=\frac{-6(+/-)\sqrt{76}} {4}[/tex]

[tex]x=\frac{-6(+/-)2\sqrt{19}} {4}[/tex]

simplify

[tex]x=\frac{-3(+/-)\sqrt{19}} {2}[/tex]