Respuesta :
The surface area of a right circular cone is SA =[tex]\pi r (r + \sqrt{ h^{2} + r^{2} } )[/tex]
The diameter (d) is equal to 20 meters and half of it is equal to the radius which is 10 meters.
The height (h) of the tank is equal to 42 meters.
Substituting the given to the equation:
SA = [tex]\pi 10 (10 + \sqrt{ 42^{2} + 10^{2} } )[/tex]
= 1670.51 square meters or the closest answer is 1,671 m2
The diameter (d) is equal to 20 meters and half of it is equal to the radius which is 10 meters.
The height (h) of the tank is equal to 42 meters.
Substituting the given to the equation:
SA = [tex]\pi 10 (10 + \sqrt{ 42^{2} + 10^{2} } )[/tex]
= 1670.51 square meters or the closest answer is 1,671 m2
The surface area of the conical grain storage tank is 1,671 m².
What is the surface area?
The surface area of a cone is the total area that is covered by the surface of the cone.
Surface area =πr(r+√h²+r²)
Where:
- π = 3.14
- h = height
- r = radius = diameter / 2 = 20 / 2 = 10 m
3.14 x 10(10 + √100 + 1764 = 1,671 m²
To learn more about a cone, please check: https://brainly.com/question/13705125
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