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The product of two numbers,A and B is 840.The difference between the two numbers, A and C is 816 given that C is the greatest number and B is the smallest 2-digit even number,Find the value of A,B,C

Respuesta :

texaschic101
B (smallest two digit even number) = 10 <=== B

AB = 840
A = 840/B
A = 840/10
A = 84 <=== A

C - A = 816
C - 84 = 816
C = 816 + 84
C = 900 <===== C

The value of A, B, and C are 84, 10, and 900 respectively.

How can we find the value of A, B, and C?

The value of A, B, and C can be found by making equations using the given information. For example, it is given that B is the smallest two-digit even number. We know that the smallest two-digit even number is 10.

We can find the value of A, B, and C as shown below:

It is given that the B is the smallest two-digit even number. We know that the smallest two-digit even number is 10.

Therefore B = 10.

It is given that the product of A and B is 840. This can be written as shown below:

AB=840

Now, substitute the value of B:

A*10=840

A=840/10

A=84

It is given that the difference between C and A is 816. It is also given that C is the greatest number. Therefore it can be written as:

C-A=816

C-84=816

C=816+84

C=900

Therefore, we have found the values of A, B, and C to be 84, 10, and 900 respectively.

Learn more about finding unknown numbers here: https://brainly.com/question/10731789

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