TJFraser
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A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system is 37.1°C, what is the specific heat capacity of the substance? Use 4.184 J / g °C for the specific heat capacity of water.

Respuesta :

EjerciciosFyQ
To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

[tex]-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w[/tex]

Clearing the specific heat of the unknown substance:

[tex]c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}[/tex]

[tex]c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}[/tex]

The formula is the heat capacity is defined as the specific heat capacity of a substance is the heat capacity of a sample of the substance divided by the mass of the sample. Specific heat is also sometimes referred to as heat capacity.

The heat capacity is 13.07g

All the data is given in the question. Using the data the calculation is as follows:-

[tex]\frac{M_wC_{ew}T_w}{mT} \\\\\\\\\frac{1150*4.148*12.1}{75*-59.4}[/tex]

After solving the equation, the correct answer is 13.07g

Hence, the specific heat is 13.07g

For more information, refer to the link:-

https://brainly.com/question/22810476

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