amal27nath
amal27nath
17-07-2016
Mathematics
contestada
(-1)^(n+1) + (-1)^n-1)=?
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caylus
caylus
17-07-2016
Hello,
[tex] (-1)^{n+1} + (-1)^{n-1} = (-1)^{n-1} ((-1)^2+1)= 2*(-1)^{n-1} [/tex]
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dalendrk
dalendrk
17-07-2016
[tex](-1)^{n+1}+(-1)^{n-1}=(-1)^n\cdot(-1)^1+(-1)^n\cdot(-1)^{-1}\\\\=(-1)^n\cdot(-1)+(-1)^n\cdot(-1)=-(-1)^n+[-(-1)^n]\\\\=\boxed{-2(-1)^n}[/tex]
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