To answer this specific problem, the acceleration of the crate is 140.6727828746177. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
Answer:
a = 6 m/s/s
Explanation:
As we know that the steel crate is pushed along the cement floor
The applied force on the crate is towards right and its magnitude is 1860 N
while the force of friction on the crate due to floor is towards left and its magnitude is 480 N
now the net force on the crate is given as
[tex]F_{net} = 1860 - 480 = 1380 N[/tex]
now from Newton's II law we know that
[tex]F_{net} = ma[/tex]
now plug in all values in it
[tex]1380 = 230 a[/tex]
[tex]a = \frac{1380}{230}[/tex]
[tex]a = 6 m/s^2[/tex]
