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contestada

A 0.40-kg object connected to a light spring with a force. constant of 19.6 N/m oscillates on a frictionless horizontal. surface. If the spring is compressed 4.0 cm and released. from rest, determine (a) the maximum speed of. the object, (b) the speed of the object when the spring is. compressed 1.5 cm, and (c) the speed of the object when. the spring is stretched 1.5 cm. (d) For what value of x. does the speed equal one-half the maximum speed?

Respuesta :

meerkat18
max speed= A*w (A-ampitude 4cm, w=angular frequency) 
w^2x=kx/m 
w=under root k/m 
max speed V= 4*10^-2 * under root 19.6/0.4 
V=0.04 * under root 49=0.04*7 
V=0.28m/sec 

B) use formula 
v=w * under root(A^2-x^2) 

C) the answer will be same as of (B)

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