1 second faster was the trip back home .
Step-by-step explanation:
Here we have , Joseph is driving at an average of 50 miles per hour on a 330-mile road trip. On the way back, Joseph was about to average 60 miles per hour. We need to find How much faster was the trip back home . Let's find out:
We know that , [tex]Speed = \frac{Distance}{time}[/tex]
⇒ [tex]Speed = \frac{Distance}{time}[/tex]
⇒ [tex]50 = \frac{330}{time}[/tex]
⇒ [tex]time = \frac{330}{50}[/tex]
⇒ [tex]time = 6.6.sec[/tex]
We know that , [tex]Speed = \frac{Distance}{time}[/tex]
⇒ [tex]Speed = \frac{Distance}{time}[/tex]
⇒ [tex]60 = \frac{330}{time}[/tex]
⇒ [tex]time = \frac{330}{60}[/tex]
⇒ [tex]time = 5.5sec[/tex]
So, Time difference in both trips is [tex]6.5sec-5.5sec=1sec[/tex] .
Therefore, 1 second faster was the trip back home .
