Respuesta :
[tex]\displaystyle\bf\\\lim_{x\to3}\frac{x^3+27}{x+3}=\frac{3^3+27}{3+3}=\frac{27+27}{3+3}=\frac{54}{6}=\boxed{\bf9}[/tex]
[tex]\displaystyle\bf\\\lim_{x\to3}\frac{x^3+27}{x+3}=\frac{3^3+27}{3+3}=\frac{27+27}{3+3}=\frac{54}{6}=\boxed{\bf9}[/tex]