Answer:
Explanation:
Given:
Mass, M = 35 kg
Velocity, v1 = 1 m/s
Velocity, v2 = 2 m/s
Coefficient of friction, uo = 0.16
Total force = M × a
At constant velocity, a = 0
F - Fk = 0
F = Fk
= uo × M × g
= 35 × 9.8 × 0.16
= 54.9 N
At F2 = 2 × F1
= 109.8 N
F = M × a
But a = (v - u)/t
109.8 = 35 × (2 - 1)/t
t = 1 × 35/109.8
= 0.32 s
