When a bat uses echolocation to determine the distance to an insect, it sends out a sound wave and waits to see how long the sound takes to echo back. Suppose now that a bat hears its echo 0.06 LaTeX: ss after it emitted the sound. If the speed of sound is 344.9 LaTeX: \frac{m}{s}m s, how far away is the insect in meters?

Respuesta :

Answer:

Explanation:

Distance travelled by sound in going to target( insect )  and returning back = 2d ,d is distance of target .

time t = .06 s

speed = distance / time

344.9 = 2d / .06

d = 10.35 m