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A stunt pilot of mass 49.0 kg who has been diving her airplane vertically pulls out of the dive by changing her course to a circle in a vertical plane. Part A If the plane's speed at the lowest point of the circle is 94.0 m/s , what is the minimum radius of the circle for the acceleration at this point not to exceed 4.00g ?

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lublana

Answer:

225.4 m

Explanation:

We are given that

Mass =m=49 kg

a.Speed,v=94 m/s

We have to find the minimum radius of the circle for the acceleration at this point not to exceed 4 g.

We know that

Radial acceleration,[tex]a=\frac{v^2}{R}[/tex]

Using the formula

[tex]4g=\frac{(94)^2}{R}[/tex]

[tex]R=\frac{(94)^2}{4g}[/tex]

We know that g=[tex]9.8m/s^2[/tex]

[tex]R=\frac{(94)^2}{4\times 9.8}[/tex]

[tex]R=225.4 m[/tex]

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