contestada

A force of 6.0 N pulls a box 0.40 m along a frictionless plane that is inclined at 36°. What work is being done by the pulling force?

Respuesta :

Answer:

Expression of work done is

[tex]W = Fd cos\theta[/tex]

Work done to move the sled is given as 1.94 J

Explanation:

As we know that the formula of work done is given as

[tex]W = Fd cos\theta[/tex]

here we know that

F = 6 N

d = 0.4 m

[tex]\theta = 36 degree[/tex]

so we will have

[tex]W = 6 \times 0.4 cos36[/tex]

[tex]W = 1.94 J[/tex]

Otras preguntas