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Ice-skater slides toward a sled sitting on the ice and hits it. The skater exerts a 12.6 N force on the sled at an angle of 15.3° below the horizontal. The sled then moves 15.4 m forward. How much work did the skater do on the sled? Assume friction is negligible.

Knowns Unknown

F = ____________ d = _____________ W = ?

θ = ____________

Solve for the Unknown

a. Write the equation for work
b. Insert known quantities

Respuesta :

Answer:

Expression of work done is

[tex]W = Fd cos\theta[/tex]

Work done to move the sled is given as 187.2 J

Explanation:

As we know that the formula of work done is given as

[tex]W = Fd cos\theta[/tex]

here we know that

F = 12.6 N

d = 15.4 m

[tex]\theta = 15.3 degree[/tex]

so we will have

[tex]W = 12.6 \times 15.4 cos15.3[/tex]

[tex]W = 187.2 J[/tex]

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