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A flat, wide cloud floats horizontally a few kilometers above the surface of Earth. Its lower surface carries a uniform surface charge density of -2.6×10-4 C/m2 , while there is no excess charge elsewhere in the cloud. What is the magnitude of the electric field, in newtons per coulomb, a few meters below the cloud, under the cloud’s approximate center, due to the charge distribution?

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Answer:

[tex]\frac{kQ}{r^2} r^[/tex]

Explanation:

Electric field strength= Force/unit charge

E= (kQq/r²)/q ₓ r

where r is the unit vector in the direction of unit charge

E= [tex]\frac{kQ}{r^2} r^[/tex]

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