Respuesta :
Answer:
[tex] \bar X = \frac{\sum_{i=1}^n X_i w_i}{\sum_{i=1}^n w_i}[/tex]
And replacing we got:
[tex] \bar X= \frac{2*3.5 +3*3.0 +4*3.0}{2+3+4}= \frac{28}{9}=3.11[/tex]
So then we expect an overall grad of 3.11 with those values.
Step-by-step explanation:
For this cae we have the following info
Credits Grade
2 3.5
3 3.0
4 3.0
Let X represent the grades and w, the weights(credits) we can find the expected overall grade with the following formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i w_i}{\sum_{i=1}^n w_i}[/tex]
And replacing we got:
[tex] \bar X= \frac{2*3.5 +3*3.0 +4*3.0}{2+3+4}= \frac{28}{9}=3.11[/tex]
So then we expect an overall grad of 3.11 with those values.
Given Information:
Grade in two-credit course = 3.5
Grade in three-credit course = 3.0
Grade in four-credit course = 3.0
Required Information:
Expected GPA = ?
Answer:
Expected GPA = 3.11
Step-by-step explanation:
The overall expected GPA is basically the mean or average
E(X) = μ = Sum of grades/Total credit hours
Sum of grades = ∑ weight*grade
Sum of grades = 2*3.50 + 3*3.0 + 4*3.0 = 28
Total credit hours = 2 + 3 + 4 = 9
E(X) = μ = Sum of grades/Total credit hours
E(X) = μ = 28/9
E(X) = μ = 3.11
Therefore, the expected overall grade point average of this student for the current semester is 3.11