A telephone pole is installed so that 25 feet of the pole are above ground level. A stabilizing cable is anchored to the ground 44 inches from the base of the pole. The other end of the cable is attached to the pole at a point 20 feet above ground level. To the nearest inch, how many inches long is the stabilizing cable?

Respuesta :

Ben

[tex]\huge\boxed{244\ \text{inches}}[/tex]

This problem can be solved using the Pythagorean Theorem.

Note: the height of the telephone pole is unnecessary information.

Convert the measurement in feet to inches.

[tex]20*12=240[/tex]

The length from the base of the pole to the anchor point on the ground is [tex]44[/tex] inches. The distance from the base of the pole to the anchor point on the pole is [tex]240[/tex] inches.

These are the two legs of a right triangle. The length of the stabilizing cable is the hypotenuse of the right triangle.

The Pythagorean Theorem is:

[tex]a^2+b^2=c^2[/tex]

In this formula, [tex]a[/tex] and [tex]b[/tex] are the legs and [tex]c[/tex] is the hypotenuse.

Plug in the known values.

[tex]44^2+240^2=c^2[/tex]

Swap the sides of the equation.

[tex]c^2=44^2+240^2[/tex]

Evaluate the powers.

[tex]c^2=1936+57600[/tex]

Simplify using addition.

[tex]c^2=59536[/tex]

Take the square root of both sides.

[tex]c=\pm 244[/tex]

Separate the solutions.

[tex]c=244\\c=-244[/tex]

Length and distance cannot be negative, so remove the negative solution.

[tex]c=\boxed{244}[/tex]