A sinusoidal wave moving to the left has a wavelength of 5.0 cm and a frequency of 50 Hz. At t = 0 s, the wave has a crest at x = 0 cm. What is the earliest time after t = 0 s at which there is a crest at the position x = 3.5 cm?

Respuesta :

Answer:

0.006 seconds

Explanation:

Were are told that:

At t = 0 s, the wave has a crest at x = 0 cm.

The distance between two consecutive wavelength ( λ ) given by the sinusoidal wave = 5.0 cm

And; Velocity can be expressed as: fλ

where f = 50 Hz

Velocity (V) = 50 × 5.0

V = 250 cm/s

If the crest is moved to a distance of 5.0 cm to 3.5 cm; then the distance traveled = (5.0 - 3.5) cm

= 1.5 cm

However; the earliest time (t) by the wave will be : [tex]\frac{1.5}{250}[/tex] = 0.006 seconds

The earliest time when the crest of the wave move to new position is 0.006 s.

The given parameters;

  • frequency, f = 50 Hz
  • wavelength to left, λ₁ = 5 cm
  • wavelength to left, λ₂ = 3.5 cm

The velocity of the wave is calculated as follows;

v = fλ

v = 50 x 5 = 250 cm/s

The earliest time when the crest of the wave move to new position of 3.5 cm;

the change in displacement, Δλ = 5 cm - 3.5 cm = 1.5 cm

[tex]t = \frac{\Delta \lambda}{v} \\\\t = \frac{1.5 \ cm}{250 \ cm/s} \\\\t = 0.006 \ s[/tex]

Thus, the earliest time when the crest of the wave move to new position is 0.006 s.

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