Respuesta :
Answer:
0.006 seconds
Explanation:
Were are told that:
At t = 0 s, the wave has a crest at x = 0 cm.
The distance between two consecutive wavelength ( λ ) given by the sinusoidal wave = 5.0 cm
And; Velocity can be expressed as: fλ
where f = 50 Hz
Velocity (V) = 50 × 5.0
V = 250 cm/s
If the crest is moved to a distance of 5.0 cm to 3.5 cm; then the distance traveled = (5.0 - 3.5) cm
= 1.5 cm
However; the earliest time (t) by the wave will be : [tex]\frac{1.5}{250}[/tex] = 0.006 seconds
The earliest time when the crest of the wave move to new position is 0.006 s.
The given parameters;
- frequency, f = 50 Hz
- wavelength to left, λ₁ = 5 cm
- wavelength to left, λ₂ = 3.5 cm
The velocity of the wave is calculated as follows;
v = fλ
v = 50 x 5 = 250 cm/s
The earliest time when the crest of the wave move to new position of 3.5 cm;
the change in displacement, Δλ = 5 cm - 3.5 cm = 1.5 cm
[tex]t = \frac{\Delta \lambda}{v} \\\\t = \frac{1.5 \ cm}{250 \ cm/s} \\\\t = 0.006 \ s[/tex]
Thus, the earliest time when the crest of the wave move to new position is 0.006 s.
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