Answer:
18.42 m
Step-by-step explanation:
At that point, the ball will be static, with final velocity of 0.
The initial velocity is 19.
The acceleration due to gravity is -9.8 m/s^2.
We now have to use an equation of kinematics shown below:
[tex]v_f^2=v_0^2+2as[/tex]
Where
[tex]v_f[/tex] is the final velocity
[tex]v_0[/tex] is the initial velocity
a is -9.8
s is the distance we are looking for
Lets substitute and find the answer:
[tex]v_f^2=v_0^2+2as\\0=(19)^2+2(-9.8)s\\-361=-19.6s\\s=18.42[/tex]
